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Colt1911 [192]
3 years ago
8

The regular price for admission to the

Mathematics
2 answers:
denis-greek [22]3 years ago
6 0

Answer: $5.25

Step-by-step explanation:

25/100 = 0.25

0.25 * 7 = 1.75

7 - 1.75 = 5.25

Neporo4naja [7]3 years ago
6 0
25%=1/4
7.00/4=1.75


2. Five seats of which 2 are window seats. 2/5 of the seats are window seats. 2/5 = 40/100 = 40%
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hey the question is, " The length of a rectangle is twice its width. The perimeter of the rectangle is 126 feet."​
Tema [17]

Answer:

42 = <em>l</em>

21 = <em>w</em>

Step-by-step explanation:

{l = 2<em>w</em>

{126 = 2<em>w</em> + 2<em>l</em>

126 = 2<em>w</em> + 2[2<em>w</em>]

126 = 2<em>w</em> + 4<em>w</em>

126 = 6<em>w</em>

21 = w [Plug this back into both equations to get the length of 42]; 42 = <em>l</em>

I am joyous to assist you anytime.

4 0
4 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
Can someone please help me with this
k0ka [10]

Answer: 3x^6+x^5-x^4-6x^3+x^2+3x-1

Step-by-step explanation:

 (3x^2+x-1)(x^4-2x+1)

=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1

=3x^6+x^5-x^4-6x^3+x^2+3x-1

Hope this helps!! :)

Please let me know if you have any question

5 0
3 years ago
Read 2 more answers
Sally is shopping for diapers and sees a box with 216 diapers for \$39.98 and a box with 88 diapers for \$24.99 . Which option h
Mekhanik [1.2K]
The first step is to find out the value of one diaper for each equation

39.98/216 = 0.18
Therefore one diaper is for 0.18 cents

24.99/88 = 0.28
Therefore one diaper is for 0.28 cents

At the end the first deal is better
7 0
3 years ago
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five friends choose from among 10 movies to watch. what is the probability that at least 2 of them choose the same movie?
alexdok [17]
I believe the answer is 20%
4 0
3 years ago
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