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lianna [129]
3 years ago
13

The quadrilateral ABCD is a rhombus with BD = BC. On the side

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0
The halves of the rhombus separated by line BD are equilateral triangles.
  ∠BAD = 60°
so
  ∠ADM is 0.80*60° = 48°.

∠BMD is an exterior angle to ΔAMD, so is equal to the sum
  ∠BMD = ∠BAD + ∠ADM
  = 60° +48° = 108°

∠BMD = 108°
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