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Leto [7]
3 years ago
7

How many burgers can make from 1 billion cows ?

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
That is not enough info: to answer the question u will need the weight
If the cows weigh 50.0 pounds then 59 burgers per cow
Daniel [21]3 years ago
8 0

Answer:

1.186836*10^12 burger

Step-by-step explanation:

first, there is not even 1billion cows on earth, according to statista.com, there are 989.03 million billion cows on earth in 2019. according to the genus on the quora, you can make 1200 burger from 1 cow, so 989,030,000*1200

sign, 1.186836e+12.

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The ages of Lee's mother and aunt total 83 years. If her mothers age were doubled, then her mother would be 58 years older than
NemiM [27]

Answer:

sorry i dont know

Step-by-step explanation:

6 0
3 years ago
Help me please explain do not need work just explain THANK YOU I NEED HELP
Mnenie [13.5K]
Alright, 

you will need to solve for each variable to find if they got the equation correctly or not.. 

Let's start with h 
isolate h 
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2 

h = 2(A/(b1+b2))

And that's not how they did it for h so Option D doesn't apply 


Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h

Let's see B
Also not correct they made the same mistake as with option C

Let's see A
again same mistake 
when multiplying both sides by 2 
the 2 should be as following 
2\frac{A}{h}

I believe you should contact your instructor and explain that non of the options is right. 

6 0
3 years ago
How many 1/8 portions are in 3/4
Zigmanuir [339]
1/4 = 2/8
3/4 = 6/8
2/8 * 3/1 = 6/8
1/4 * 3/1 = 3/4
6  1/8 portions are in 3/4
5 0
3 years ago
A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la
Minchanka [31]

The exponential function which represented by the values in the table is f(x)=4(\frac{1}{2})^{x} ⇒ 3rd answer

Step-by-step explanation:

The form of the exponential function is f(x)=a(b)^{x} , where

  • a is the initial value (when x = 0)
  • b is the growth/decay factor
  • If k > 1, then it is a growth factor
  • If 0 < k < 1, then it is a decay factor

The table:

→  x    :    f(x)

→ -2    :    16

→ -1     :    8

→  0    :    4

→   1    :    2

→   2   :     1

∵ f(x)=a(b)^{x}

- To find the exponential function substitute the value of x and f(x)

  by some values from the table to find a and b, at first use the

  point (0 , 4) to find the value of a

∵ x = 0 and f(x) = 4

∴ 4=a(b)^{0}

- Remember that any number to the power of zero equal 1

  except the zero

∵ b^{0}=1

∴ 4 = a(1)

∴ a = 4

Substitute the value of a in the equation

∴ f(x)=4(b)^{x}

- Chose any other point fro the table to find b, lets take (1 , 2)

∵ x = 1 and f(x) = 2

∴ 2=4(b)^{1}

∴ 2 = 4 b

- Divide both sides by 4

∴ b=\frac{2}{4}=\frac{1}{2}

- Substitute the value of b in the equation

∴ f(x)=4(\frac{1}{2})^{x}

The exponential function which represented by the values in the table is f(x)=4(\frac{1}{2})^{x}

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

8 0
3 years ago
Read 2 more answers
Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
4 years ago
Read 2 more answers
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