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timurjin [86]
4 years ago
12

What is 168/25 as a mixed number

Mathematics
2 answers:
kifflom [539]4 years ago
6 0

168/25 as a mixed number is 6.72. 168/25 turns into 6 18/25 which is equal to 6.72. Hope this helps! Plz mark me as brainliest! :)

Andreas93 [3]4 years ago
3 0

6 7/25 25x6 is 150 7 is left out of the rest

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Taylor fills a jar with marbles. Each marble weighs 0.04 pound. The total weight of the jar is 3/5 of a pound. How many marbles
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If (y) varies directly with x, and y=3 when x=0.2, what is the value of (y) when x=1?
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since it varies directly, we form an equation ,  
Y =kX  where k is a constant
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3 years ago
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100 random students are surveyed outside of the student center on campus. Let V denote that the student has a Visa credit card a
mote1985 [20]

Answer:

(a) The value of P (M | V) is 0.30.

(b) The value of P (M^{c} | V) is 0.70.

(c) The value of P (V | M) is 0.375.

(d) The value of P(V^{c}|M) is 0.625.

Step-by-step explanation:

It is provided that,

<em>V</em> = a student has a Visa card

<em>M</em> = a student has a Master card

N = 100, n (<em>V</em>) = 40, n (<em>M</em>) = 32 and n (<em>V</em> ∩ <em>M</em>) = 12.

The probability of a student having visa card is:

P(V) = \frac{n(V)}{N}= \frac{40}{100}=0.40

The probability of a student having master card is:

P(M) = \frac{n(M)}{N}= \frac{32}{100}=0.32

The probability of a student having  visa card and a master card is:

P(V\cap M) = \frac{n(V\cap M)}{N}= \frac{12}{100}=0.12

The conditional probability of an event, say A, given that another event, say B, has already occurred is,

P(A|B)=\frac{P(A\cap B)}{P(B)}

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. P (M^{c} | V) as follows:

P (M^{c} | V)=1-P(M|V)=1-0.30=0.70

Thus, the value of P (M^{c} | V) is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. P(V^{c}|M) as follows:

P(V^{c}|M)=1-P(V|M)=1-0.375=0.625

Thus, the value of P(V^{c}|M) is 0.625.

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