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Kobotan [32]
3 years ago
9

What is 1.70 times 8.5

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0
The answer is 14.45. Hope this helps
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Hank is buying new curtains for his house. Each window will need 2 curtains panels to cover it. He has a total of 16 windows in
fenix001 [56]

Answer:

He spends $298

Step-by-step explanation:

He has 16 curtains

16*2=32

That answer is how many he needs

Now multiply that by the price

32 curtains for $29

32*29=928

The answer is $928

5 0
3 years ago
Read 2 more answers
Carl has three lengths of cable,
elena-s [515]
Lowest common denominator for 3,4,6 is 12

5/6 = 10/12
1/4 = 3/12
2/3 = 8/12

a)
10/12 + 3/12 = 13/12 = 1 1/12
So you need to use first and second cables

b)
3/12 + 8/12 = 11/12
To reach 1 yard Carl need 1/12 yard cable
6 0
3 years ago
Please help me fast ​
Andre45 [30]

Answer:

...............................4650

8 0
3 years ago
How do you solve (X-9)(X+11)
soldi70 [24.7K]
FOIL
x^2+11x-9x-99
x^2+2x-99
5 0
3 years ago
Read 2 more answers
Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

We are given the following integral:

\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

8 0
3 years ago
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