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3 years ago

What is 1.70 times 8.5

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

The answer is 14.45. Hope this helps

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Hank is buying new curtains for his house. Each window will need 2 curtains panels to cover it. He has a total of 16 windows in

fenix001 [56]

Answer:

He spends $298

Step-by-step explanation:

He has 16 curtains

16*2=32

That answer is how many he needs

Now multiply that by the price

32 curtains for $29

32*29=928

The answer is $928

5 0

3 years ago

Read 2 more answers

Carl has three lengths of cable,

elena-s [515]

Lowest common denominator for 3,4,6 is 12

5/6 = 10/12
1/4 = 3/12
2/3 = 8/12

a)
10/12 + 3/12 = 13/12 = 1 1/12
So you need to use first and second cables

b)
3/12 + 8/12 = 11/12
To reach 1 yard Carl need 1/12 yard cable

6 0

3 years ago

Please help me fast

Andre45 [30]

Answer:

...............................4650

8 0

3 years ago

How do you solve (X-9)(X+11)

soldi70 [24.7K]

FOIL
x^2+11x-9x-99
x^2+2x-99

5 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$

Coming back to x:

We have that:

$x = 3\sin{\theta}$

$\sin{\theta} = \frac{x}{3}$

Applying the arcsine(inverse sine) function to both sides, we get that:

$\theta = \arcsin{(\frac{x}{3})}$

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

8 0

3 years ago