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Vanyuwa [196]
3 years ago
10

Which equation below is a quadratic function translated up 5 units?

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

y=x2 + 5

Step-by-step explanation:

A quadratic function is where the graph is in the shape of a "U" or parabola.

An example of a quadratic function if the form: y= ax^2+bx+c

What all formulas have in common is that at the end of the equation there will be a variable with no x paired with it( aka the y-intercept; the 'c' equivalent in the example formula i gave ), this letter is what tells the graph to move up or down the y-axis.

So in the answers given, ask yourself, " is there any y-intercept? And if so, is it plus 5?"

** plus 5 is the graph moving up 5 units on the y-axis

And you'd find the first answer is the only equation with a y-inter.

** side note: In y = (x + 5)^2, the 5 isn't a y-inter. bc it's inside the parenthesis. Numbers in the para. (like 5) tells the graph to move left or right ( if it is a "-" it's right and "+" is left)

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tatyana61 [14]

Answer:

  3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

  \dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}

__

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

  \dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}

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It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

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Please discuss this question with your teacher.

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