Answer:
According to the diagram, is the polar angle (the "vertical" angle made with the positive z-axis) and is the azimuthal angle (the "horizontal" angle made with the positive x-axis), so the convention used here is to take
Then for the spherical point (1, π/4, π/2), we have the corresponding Cartesian point (x, y, z), where
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
6 x 2= 12
12 x 3= 36
1,32 2,16, 4,8
That's all I got so it's 3
Sorry if I got it wrong or missed some
Answer:
10 years
Step-by-step explanation:
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
