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4 years ago

Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

1 answer:

3 0

Given that <span>Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

The number of days it takes him to finish the book is given by 400 / 25 = 16 days.

In 0 days, he has 400 pages remaining and in 16 days he has 0 pages remaining.

Therefore, the graph that represents the situation is a</span><span> graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are (0, 400) and (16, 0).</span>

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Use the result of the previous question and write it

fiasKO [112]

Answer:

1-3c/4d+5

Step-by-step explanation:

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4 0

3 years ago

Mary earned $200 for doing some jobs for neighbors. She spent $31.66 at the mall and $48.18 at the convenience store. She put th

Y_Kistochka [10]

Subtract the amount she spent from the amount she earned:

200 - 31.66 - 48.18 = 120.16

The answer would be A.

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3 years ago

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0

4 years ago

How do I solve for number 15

Mama L [17]

X=3 y=1
2x3 = 6 and 3x1 = 3. 6+3 = 9.
Hope this helped!

6 0

3 years ago

WC= 15 and CO = 17, what is OW?

soldier1979 [14.2K]

We know that triangle COW is a right triangle by the Tangent to a Circle Theorem.

So, we can use Pythagorean Theorem to find OW.

OW² + WC² = CO²

OW² + 15² = 17²

OW² + 225 = 289

OW² = 64

OW = 8

4 0

3 years ago