Answer: 2^14
Step-by-step explanation:
Answer:
NO
Step-by-step explanation:
Draw a triangle and label the sides a, b and c. Now we must know the rule you can use for drawing any triangle:
A+B> c
A+C>B
B+C>A
Sub you numbers into the rule:
8+10, is it greater that 19?
No, 8+10=18 and 18<19
This is proof that you can not draw a triangle with the side lengths of 8m, 10m and 19m.
<span>Given :
f(x)= 3 x – 6
and
g(x) = x –2
f(x)/g(x) = (</span>3 <span>x – 6 </span>)/(x - 2)
simplifying
f(x)/g(x) = 3( x – 2 )/(x - 2<span>)
</span><span>f(x)/g(x) </span>= 3
Domain : set of all real numbers,where x is not equal 2
The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
<h3>How to determine the new vertices?</h3>
The vertices are given as:
a (-6,-7)
b(-3,-10)
c(-5,2)
The transition rule is given as
(x,y)-->(x,y-3)
So, we have
a' = (-6, -7 - 3)
a' = (-6, -10)
b' = (-3, -10 - 3)
b' = (-3, -13)
c' = (-5, 2 - 3)
c' = (-5, -1)
Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
Read more about translation at:
brainly.com/question/4289712
#SPJ1
= (cos2x+1)(cos2x+1)/4