Exponent rule : a^-x = 1/a^x
x^-9 * x^-2 =
1/x^9 * 1/x^2 = (when multiplying exponents with same base, add exponents)
1/x^(9 + 2) =
1/x^11
If f(x) = 5x - 16, then value of f(9) is 29
<em><u>Solution:</u></em>
Given function is f(x) = 5x - 16
We are asked to find the value of f(9)
To find the value of f(9), we have to substitute x = 9 in given function and solve the function
Therefore, substitute x = 9
f(x) = 5x - 16
f(9) = 5(9) - 16
Multiply 5 with 9 which gives 45
f(9) = 45 - 16
Subtract 16 from 45
f(9) = 29
Thus value of f(9) is 29
Answer:
x = 0
Step-by-step explanation:
Subtract 25x^2 from both sides
24x^2 + bx^2 - 25x^2 - 25x^2
Simplify
bx^2 - x^2 = 0
Factor bx^2 - x^2: x^2(b - 1)
bx^2 - x^2
Factor out common term x^2
= x^2 (b - 1)
x^2(b - 1) = 0
Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0
x^2 = 0
Apply rule x^n = 0 x = 0
x = 0
