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3 years ago

Brandon makes 4/5 of his free throw shots when he play. If he takes 45 shots how many is he expected to make

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

5 0

4/5 = 80%

80% of 45 is

.8 x 45 = 36

He is expected to make 36 of his shots

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the intake pipe can fill a certain tank in 6 hours when the outlet pipe is closed, but with the outlet pipe open it takes 9 hour

Leona [35]

The outlet pipe will take 18 hours to empty the tank.

Step-by-step explanation:

Number of hours taken by inlet pipe to fill the tank=6

work done by the inlet pipe in 1 hour=1/6

Number of hours taken by the inlet pipe to fill the tank with the outlet pipe open=9

work done by the inlet pipe in 1 hour with outlet pipe open=1/9

we have to determine the time taken by the outlet pipe to empty the tank

The inlet and outlet pipe does the opposite work.

$\\time\ taken\ by\ the\ outlet\ pipe\ to\ empty\ the\ tank=x\\work\ done\ by\ the\ outlet\ pipe\ in\ 1\ hour=1/x\\(1/6-1/x)9=1\\1/6-1/x=1/9\\1/x=1/6-1/9=3/54\\x=54/3=18$

The outlet pipe takes 18 hours to empty the tank.

6 0

3 years ago

Can anyone help me please??

allochka39001 [22]

Answer:

-20x / (x-12) = y

Step-by-step explanation:

3/x - 5/y = 1/4

Multiply each side by 4xy to clear the fractions

4xy ( 3/x - 5/y = 1/4)

Distribute

12y - 20x = xy

Subtract 12y from each side

-20x = xy -12y

Factor out y

-20x = y(x-12)

Divide each side by (x-12)

-20x / (x-12) = y

4 0

4 years ago

-8 = -19 + C plz answer this

TiliK225 [7]

Answer:

c = 11

Step-by-step explanation:

-8 = -19 + 11

4 0

3 years ago

Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify t

laiz [17]

Answer:

There is sufficient evidence to conclude that child booster seats meet the specific requirement.

Step-by-step explanation:

Sample: 697, 759, 1266, 621, 569, 432

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{4344}{6} = 724$

Sum of squares of differences = 415616

$S.D = \sqrt{\frac{415616}{5}} = 288.31$

We are given the following in the question:

Population mean, μ = 1000 hic

Sample mean, $\bar{x}$ = 724

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, s = 288.31

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 1000\text{ hic}\\H_A: \mu < 1000\text{ hic}$

We use one-tailed(left) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{724 - 1000}{\frac{288.31}{\sqrt{6}} } = -2.344$

Now, $t_{critical} \text{ at 0.05 level of significance, 5 degree of freedom } = -2.015$

Calculation the p-value from table,

P-value = 0.033

Since,

Since, the p value is lower than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that the measurement is less than 1000 hic.

Thus, there is sufficient evidence to conclude that child booster seats meet the specific requirement.

4 0

4 years ago

PLEASE HURRY 3x - 10 - 2x +5 What is the value of x? -5 1 3 15

Reil [10]

Itsssssssssssssssssssssss -5

4 0

3 years ago

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