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Lana71 [14]
3 years ago
8

What type of angle is this​

Mathematics
1 answer:
prohojiy [21]3 years ago
8 0

Answer:

Congruent

Step-by-step explanation:

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A new​ phone-answering system installed by a certain utility company is capable of handling ten calls every 10 minutes. Prior to
Mrrafil [7]

Answer:

0.0137

Step-by-step explanation:

Let X be the random variable that measures the number of incoming calls every ten minutes.

If the incoming calls to the system are Poisson distributed with a mean equal to 5 every 10 minutes, then the probability that there are k incoming calls in 10 minutes is

\bf P(X=k)=\frac{e^{-5}5^k}{k!}

If the phone-answering system is capable of handling ten calls every 10 minutes, we want to find

P(X>10), or the equivalent 1 - P(X≤ 10).  

But

1 - P(X≤ 10)= 1 -(P(X=0)+P(X=1)+...+P(X=10)) =

\bf 1-\left (\frac{e^{-5}5^0}{0!}+\frac{e^{-5}5^1}{1!}+...+\frac{e^{-5}5^{10}}{10!}\right)=\\=1-e^{-5}\left(\frac{5^0}{0!}+\frac{5^1}{1!}+...+\frac{5^{10}}{10!}\right)=1-0.9863=0.0137

So, the probability that in a 10-minute period more calls will arrive than the system can​ handle is 0.0137

6 0
3 years ago
What's the answer?<br> Idk it bc I'm stupid and I don't feel like doing it
padilas [110]
The initial height is 4
after 2 seconds, the height is 8
Brainliest answer, please?
6 0
3 years ago
Drag each number to the correct location on the table. Not all numbers will be used.
Airida [17]

Answer:

Complete Table:

Result of Roll ------ Frequency ------- Experimental Probability

1 --------------------------- 22 ------------------- 0.176

2 --------------------------- 13 ------------------- 0.104

3 --------------------------- 18 ------------------- 0.144

4 --------------------------- 29 ------------------- 0.232

5 --------------------------- 37 ------------------- 0.296

6 --------------------------- 6 ------------------- 0.048

Step-by-step explanation:

Required: Complete the table

The table is divided into 3:

1. Result of Roll

2. Frequency (F)

3. Experimental Probability (P)

The relationship between (2) and (3) is:

P = \frac{F}{N}

Where

N = Number of Rolls

N = 125

For Roll of Result = 2

Frequency = 13

The probability is calculated as thus:

P = \frac{13}{125}

P = 0.104

For Roll of Result = 3

Probability = 0.144

The Frequency is calculated as thus:

0.144 = \frac{F}{125}

F = 0.144 * 125

F = 18

For Roll of Result = 4

Frequency = 29

The probability is calculated as thus:

P = \frac{29}{125}

P = 0.232

For Roll of Result = 5

Probability = 0.296

The Frequency is calculated as thus:

0.296 = \frac{F}{125}

F = 0.296* 125

F = 37

For Roll of Result = 6

Frequency = 6

The probability is calculated as thus:

P = \frac{6}{125}

P = 0.048

For Roll of Result = 1.

To get the frequency; we subtract the sum of frequencies of roll of results 2 to 6 from the total number of rolls.

In other words:

Frequency of 1 = Total Rolls - (Frequency of 2 + Frequency of 3 + Frequency of 4 + Frequency of 5 + Frequency of 6)

Frequency of 1 = 125 - (13 + 18 + 29 + 37 +6)

Frequency of 1 = 125 - 103

Frequency of 1 = 22

The probability is calculated as thus:

P = \frac{F}{N}

P = \frac{22}{125}

P = 0.176

7 0
3 years ago
If a pound of turkey costs ​$0.82, how much will n pounds​ cost?
Gennadij [26K]
$0.82n is the answer
7 0
3 years ago
Thirty students at Eastside High School took the SAT on the same Saturday. Their raw scores are given next. 1,450 1,620 1,800 1,
IRISSAK [1]

Answer:

Number of students who scored atleast 1700 but less Than 2100 = 17

Step-by-step explanation:

Given the data :

1,450 1,620 1,800 1,740 1,650 1,800 2,010 1,780 1,840 1,490 1,620 1,480 2,390 1,640 1,830 1,710 1,900 1,910 1,950 1,820 1,590 2,350 2,260 1,870 1,530 1,950 2,000 1,830 1,980 2,100

Class interval __ Frequency

1400 - 1599 ____ 5

1600 - 1799 ____ 7

1800 - 1999 ____12

2000 - 2199 ___ 3

2200 - 2399 ___ 3

Number of students who scored atleast 1700 but less Than 2100 = 17

8 0
3 years ago
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