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son4ous [18]
3 years ago
15

HELP!!! I need help ASAP!!! PLEASE!!

Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0
Top second one under grass and across from minor 77.972.
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Because I love books and helping people find things. The library is like my habitat. My home, reading is everything to me.
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3 years ago
Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi
RSB [31]

Answer:   (0.273,\ 0.783)

Step-by-step explanation:

Given : Total number of students who are asked to complete a survey anonymously : n= 240

Number of students

The proportion report that they have experienced bullying =54

Then , the proportion that students have experienced bullying =p=\dfrac{54}{240}=0.225

Significance interval : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

The confidence interval for the true proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.225\pm (1.96)\sqrt{\dfrac{(0.225)(1-0.225)}{240}}\\\\\approx0.225\pm0.0528\\\\=(0.255-0.528,\ 0.255+0.528)\\\\=(0.273,\ 0.783)

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3 years ago
Write the function tan(<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%5Cpi%20%7D%7B4%7D%20-x" id="TexFormula1" title="\frac{3\pi
Alenkasestr [34]

Step-by-step explanation:

\tan( \frac{3\pi}{4}- x)  =  \frac{ \tan( \frac{3\pi}{4} ) -  \tan(x)  }{1 +  \tan( \frac{3\pi}{4} ) \tan(x)}

Since tan(3pi/4) = -1

\tan( \frac{3\pi}{4}- x)  =  \frac{ - 1 -  \tan(x)  }{1  -  \tan(x)}

=  \frac{ \tan(x)  + 1}{ \tan(x)  - 1}

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Solve 6x+3y=−1 for y
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3y=-6x-1
y=-2x-1/3 is the answer
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3 years ago
Read 2 more answers
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