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kirill [66]
3 years ago
10

Are humans real

Mathematics
2 answers:
nignag [31]3 years ago
7 0
AAAAAAAAAAAAAAAAAAAAAaaaaaAaAAaaaAAaAAAaAAaA
Alenkinab [10]3 years ago
4 0

Answer:

aaaaaaaaaaaaaaaaaaaa

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In the graph, the triangle on the top is the pre-image.
Ber [7]

Answer:

option a

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
50 POINTS!!!!!
Makovka662 [10]

We can adjust the data by adding 4 to everything before we calculate the statistics.  Or we can calculate the statistics on the given data and just add 4 to everything at the end.  We'll get the same answer either way.

Let's sort the seven data points:  5 5 5 7 7 9 10

Those add up to 48 so the mean is 48/7 = 6.9

The one in the middle is 7 so the median = 7

The mode is the most common one, mode = 5

The range is the difference between max and min, so range = 10 - 5 = 5

In the second week we add four to everything.  Since that adds four to the min and max, the range doesn't change.

Answer: mean=10.9, median=11, mode=9, range=5

7 0
3 years ago
Name this parent function f(x)=(1)/(x+3)-5
mash [69]

Answer:

F(x)=IxI

Step-by-step explanation:

8 0
3 years ago
Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you
gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

  • scenario A: selecting a black card
  • scenario B: selecting a red card that is less than 5
  • scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

  • 1/2 = 13/26
  • 2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

7 0
2 years ago
How do i do this???????
Fittoniya [83]

Answer:

2y-4-6y-12=4

-4y=20

y= -5

Step-by-step explanation:

because (y+2)(y-2)=y^2-4

so we have the step to let the every part have the same denominator y^2-4

2(y-2)/(y+2)(y-2)  -6(y+2)/(y-2)(y+2)=4/(y-2)(y+2)

the denominators are the same so the equality .we just need the part over be the same 2y-4-6y-12=4

y= -5

3 0
3 years ago
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