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kirill [66]
3 years ago
10

Are humans real

Mathematics
2 answers:
nignag [31]3 years ago
7 0
AAAAAAAAAAAAAAAAAAAAAaaaaaAaAAaaaAAaAAAaAAaA
Alenkinab [10]3 years ago
4 0

Answer:

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You might be interested in
What is it called when writing a number by adding the value of each digit
Neko [114]

Answer:

Expanded form

Step-by-step explanation:

Expanded form or expanded notation is a system of writing numbers to see the value of each individual digits. The number are written in the form of tens, hundreds and ones etc. The expanded form of 44 will be 40 +4 where 4 is at ones place and 40 is at tens place.

5 0
3 years ago
In a right triangle, the hypotenuse has endpoints P(–3, 2) and Q(1, –3).
allsm [11]
52, i am so sorry this is probably incorrect
4 0
3 years ago
Read 2 more answers
Please help me with this I need it now :)
arsen [322]

Answer:

reverse it x-15=4 do 15+4=x

Step-by-step explanation:

6 0
3 years ago
A student answered 86 problems on a test correctly and received a grade of 98%. How many problems were on the test, if all the p
balu736 [363]

Answer:

88 problems

Step-by-step explanation:

Set this problem up as fractions

86/x = 98/100

Cross multiply

86 × 100 = x × 98

8600 = 98x

Divide both sides by 98

87.75... = x

Round to nearest whole number

87.75 rounds up to 88

88 problems

7 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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