How many four element subsets of \{1, 2, 3, 4, 5, 6, 7\}{1,2,3,4,5,6,7} have 11 as an element but do not have 77 as an element
levacccp [35]
If we fix 1 to be an element of a subset of size 4, then we can choose from 5 other elements (2, 3, 4, 5, and 6) to fill the other 3 spots in the subset. So there are
such subsets.
3
Step-by-step explanation:
1.3z + 1.5 = 5.4
Make z the subject in the equation by making it stand alone, by so doing, the transferred figures will have a change in sign i.e if it's a negative sign that's gonna be transferred it will change into a positive sign and vice versa.
The equation will this be; 1.3z = -1.5 + 5.4
1.3z = 3.9
Divide both sides by the co-efficient of the unknown figure. In other words, you'll divide both sides by the number beside the unknown letter.
z = 3.
Answer:
this is a trapezoidal prism
I hope this helps you
Parralellogram Area=base×height
P.A.=12×4
P.A.=48
