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Artemon [7]
3 years ago
6

You have this information about ΔABC, ΔDEF, and ΔGHI:

Mathematics
2 answers:
pychu [463]3 years ago
8 0
<span>ΔABC, ΔDEF, and ΔGHI
</span>
I think all triangles are congruent. 2 sides and 1 angle of each triangle is has the same measure. Making these triangles congruent in SAS theorem.
zavuch27 [327]3 years ago
8 0

Answer: ΔABC, ΔDEF, and ΔGHI

Step-by-step explanation:

Given: In ΔABC, ΔDEF, and ΔGHI:

AB = DF               AB = GI

BC = HI                DE = HI

m∠B = m∠D = m∠I

In ΔABC and ΔGHI

AB = GI  [given]

BC = HI  [given]

m∠B =  m∠I  [given]

[ here m∠B and m∠I are the included angle of ΔABC and ΔGHI]

∴ ΔABC ≅ ΔGHI [by SAS congruence postulate]

In ΔABC and ΔDEF

AB = DF [given]

BC = DE [ Since BC = HI  and DE = HI so by transitive property BC = DE]

m∠B =  m∠D  [given]

[ here m∠B and m∠D are the included angle of ΔABC and ΔDEF]

∴ ΔABC ≅ ΔDEF [by SAS congruence postulate]

Now, since ΔABC ≅ ΔGHI and ΔABC ≅ ΔDEF

⇒  ΔGHI ≅ ΔDEF [transitive property]

Hence, all the given triangles ΔABC, ΔDEF, and ΔGHI are con gruent to each other.

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Step-by-step explanation:

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4 0
3 years ago
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The solution to a quadric equation are x=2 and x=7. If k is a nonzero constant which of the following must be equal to the quadr
nikklg [1K]

Answer:

The quadratic equation form is x² - 9 x + 14  = 0            

Step-by-step explanation:

Given in the question as ,

The solution of quadratic equation are x = 2   and x = 7

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And  sum of roots = \frac{ - b}{a}

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So, 2 + 7 = \frac{ - b}{a}

Or, 2 × 7 =  \frac{c}{a}

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Put this value of b and c in standard form of quadratic equation

I.e ax² + bx + c = 0

Or, ax² - 9 ax + 14 a = 0

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Hence ,  The quadratic equation form is x² - 9 x + 14  = 0      Answer

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3 years ago
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2 years ago
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AnnyKZ [126]
True cus I did that before
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