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Liula [17]
3 years ago
13

For what value of x is sin x = cos 19º, where 0°< x < 90°?

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

  71°

Step-by-step explanation:

The cosine of an angle is equal to the sine of its complement:

  cos(19°) = sin(90° -19°) = sin(71°)

Comparing to the given expression, we see that x = 71°.

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Pls help if you actually can
Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A.  The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB  (Alternate Interior Angles)

∠BPE ≅ ∠BCG  (Alternate Interior Angles)

∠GBC ≅ ∠EBP  (Vertical Angles)

C.  To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375  

PE = 260 ft

BE/425 = 225/325  

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

#SPJ1

5 0
1 year ago
Please Help!!! I will give Brainliest to the correct answer!!
Rudiy27

Answer:

A. NO

B.  NO

C. YES

D. YES

E. NO

F. NO

Step-by-step explanation:

7 0
3 years ago
Calculate the following numbers into scientific notation (include units)
inna [77]
<span>7800nm + 95pm = (7800x 10^-9) + (95x10^-12) = 7.800095</span><span>x10^-6=</span><span>7.800095mm
</span>
2500nm - 7pm    = (2500x 10^-9) + (7x10^-12) = 2.50007x10^-6 = 2.50007mm

(65x10^4m) x (4.5x10^-6s-1) = clarify this question

(24x10^5m) / (2x10^-8s) = clarify this question
                                                                              






7 0
3 years ago
The graph below describes the journey of a train between two cities
UkoKoshka [18]

Answer:

Step-by-step explanation:

To find : Acceleration in first 15 min . Distance between two cities  Average speed of journey

Solution:

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                    Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Distance between two cities

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

Average Speed of journey = 125/2  = 62.5  km/hr

Acceleration in first 15 min = 200  km/h²

Distance between two cities = 125 km

Average Speed of journey =  62.5  km/hr

Hope this helps..

3 0
3 years ago
Read 2 more answers
Help me please! correct answer gets brainliest!!
MrRa [10]

47 - 19 = 28

28/4 = 7

At most they can spend 7 hours

The solution is

T = (47-19)/4

T = 28/4

T = 7

I think that solution is what your teacher is asking for, i'm not certain but ik the answer should be 7 hours.

4 0
2 years ago
Read 2 more answers
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