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olga55 [171]
4 years ago
7

A Square has its length and width increase by 2 feet and 4 feet respectively so that it is now a rectangle. The perimeter of the

new rectangle is 8 feet less than twice the original perimeter. What was the original perimeter? Show I'll work the leads answer
Mathematics
1 answer:
natali 33 [55]4 years ago
4 0

Answer:

Step-by-step explanation:

Let L represent the length of one side of the square.

A Square has its length and width increase by 2 feet and 4 feet respectively so that it is now a rectangle. This means that the length of the new rectangle would be L - 2 and its width would be L - 4

The perimeter of the original square is 4L.

The perimeter of the new rectangle is 8 feet less than twice the original perimeter. This means that

2[(L - 2) + (L + 4) = 4L × 2 - 8

2(L - 2 + L + 4) = 8L - 8

4L + 4 = 8L - 8

8L - 4L = 4 + 8

4L = 12

L = 12/4 = 3

The original perimeter of the square is

3 × 4 = 12 feet

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<em>Answer:</em>

∠WVR = 156

<em>Step-by-step explanation:</em>

Angles in a triangle add up to 180

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∠SRT = 180 - ∠WVR

24 = 180 - ∠WVR

24 - 180 = - ∠WVR

-156 = - ∠WVR

∠WVR = 156

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