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Vadim26 [7]
3 years ago
10

What is the value of n in the simplified expression? (4k7)3= 4n ·(k7) 3= 64k21

Mathematics
2 answers:
Nesterboy [21]3 years ago
5 0
Given:
(4k⁷)³ = 4n(k⁷)³

Note that (aˣ)ⁿ = aˣⁿ

Expand the left and right sides.
4³k²¹ = 4nk²¹
Divide each side by k²¹.
4³ = 4n
Divide each side by 4.
4² = n
Therefore
n = 4² = 16

Answer: n = 16

fenix001 [56]3 years ago
3 0

Answer:

the answer is

Step-by-step explanation:

n=3

m=16

i hope i help :)

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18-(4x+3y) if x = -5 and y = 3
zaharov [31]

Answer:

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2 years ago
What are the truth values of Q v ~R?
GREYUIT [131]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Which of the following is a point-slope equation of a line that passes through
Mademuasel [1]

Answer:

The Answer is: y = -2/3x + 10/3

Step-by-step explanation:

Given points (-1, 4) and (8, -2) first find the slope:

m = (y - y1)/(x - x1)

m = (4 - (-2)) / (-1 - 8)

m = 4 + 2 / -9

m = -6/9 = -2/3

Use the point slope form and point (8, -2) and slove for y:

y - y1 = m(x - x1)

y - (-2) = -2/3(x - 8)

y + 2 = -2/3x + 16/3

y = -2/3x + 16/3 - 2

y = -2/3x + 16/3 - 6/3

y = -2/3x + 10/3

Proof using the point (-1, 4):

f(-1) = -2/3(-1) + 10/3

= 2/3 + 10/3

= 12/3 = 4, giving point (-1, 4)

Hope this helps! Have an Awesome Day!! :-)

4 0
3 years ago
HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!! CERTAIN ANSWERS AND I WILL MARK YOU AS BRAINIEST!!!! WISH YOU BEST OF LUCK HOPEFULLY ITS N
AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
3 years ago
The pair of points is on the graph of an inverse variation. find the missing value. (5,4) and (x,7)
d1i1m1o1n [39]
One form of the relation of inverse variation is y = k/x.

first step:  Find the value of k:    Taking the values x=5 and y = 4, 4=k/5, or k=20.  Then,   y = 20/x.

Next:  Let y = 7 and find the corresp. value of x:  7=20/x, or 7x=20, or

x = 20/7    (answer) 
7 0
3 years ago
Read 2 more answers
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