Answer:
Domain = all real numbers (-∞,+∞)
range = [0 , + infinity)
F(x) = 2x+1
f(-4) = 2(-4)+1
= -8+1
= -7
i hope it helps
I'll tell you which transformation you have to apply to draw the new graph:
![p(x) \to p(x-1)](https://tex.z-dn.net/?f=p%28x%29%20%5Cto%20p%28x-1%29)
Transformations like
translate the function horizontally, k units right if k is negative, k units left if k is positive. In this case, k is negative, so you shift the graph 1 unit to the right.
![p(x-1) \to -p(x-1)](https://tex.z-dn.net/?f=p%28x-1%29%20%5Cto%20-p%28x-1%29)
Transformations like
stretch the function vertically. If k is negative, they also reflect the graph about the x axis. In this case, k is -1, so you reflect the graph and then stretch with factor 1 (i.e. you don't stretch). So, you reflect the graph about the x axis.
![-p(x-1) \to -p(x-1)-3](https://tex.z-dn.net/?f=-p%28x-1%29%20%5Cto%20-p%28x-1%29-3)
Transformations like
translate the function vertically, k units down if k is negative, k units up if k is positive. In this case, k is negative, so you shift the graph 3 unit down.
Follow the bold instruction (in that order!) and you'll have the graph of the new function.
Answer:
27 ft
Step-by-step explanation:
A=Bh
135=B*5
divide 135/5=27
Answer:
0 ≤ z ≤ 9, x^2 + y^2 ≤ 9
Step-by-step explanation:
z = 9
radius = 3
The region that lies on or below has a plane z= 9
This means that z ≤ 9
The region that lies on or above the disk in the xy plane is described by z ≥ 0
The combination inequality is 0 ≤ z ≤ 9
To restrict the disk centred at the origin with radius 3 is to restrict the x and y values. We have
x^2 + y^2 ≤ r^2
x^2 + y^2 ≤ 3^2
x^2 + y^2 ≤ 9
The full set of inequalities is
0 ≤ z ≤ 9, x^2 + y^2 ≤ 9