All categories

3 years ago

Find the area of the trapezoid below.

Mathematics

1 answer:

Pani-rosa [81]3 years ago

7 0

Answer: 54 cm²

Step-by-step explanation: In this problem, we're asked to find the area of the trapezoid shown. A trapezoid is a quadrilateral with one pair of parallel sides.

The formula for the area of a trapezoid is shown below.

$Area =\frac{1}{2} (^{b} 1 + ^{b}2)h$

The b's represent the bases which are the parallel sides and h is the height.

So in the trapezoid shown, the bases are 6 cm and 12 cm and the height is 6 cm. Plugging this information into the formula, we have $\frac{1}{2} (6 cm +12cm)(6 cm)$ .

Next, the order of operations tell us that we must simplify inside the parentheses first. 6 cm + 12 cm is 18 cm and we have $\frac{1}{2}(18 cm)(6 cm)$ .

$\frac{1}{2} (18 cm)$ is 9 cm and we have 9 cm · 6 cm of 54 cm²

So the area of the trapezoid shown is 54 cm².

You might be interested in

Which of the following equations have complex roots?

valkas [14]

Answer:

Step-by-step explanation:

Completing the square: (x+ 7/2)^2 = -2 + 49/4 = 41/4, in the next step you'll be square rooting a positive number so it'll have real roots.

Completing the square: (x+3/2)^2 = -9 + 9/4 = -27/4, you'll next be square rooting a negative number, so it'll have complex roots

Completing the square: (x-5/2)^2 = -1 + 25/4 = 21/4, next you'll square root a positive number, so real roots

Completing the square: (x+7/2)^2 = 2 + 49/4 = 57/4, square root a positive number, so real roots.

8 0

2 years ago

Perform the indicated operation of 4.2+1.9

kykrilka [37]

Answer:

6.1

Step-by-step explanation:

hope it helps<3

4 0

3 years ago

Math (2) Help please

eduard

What am i supposed to help with, can you show me?

8 0

2 years ago

Someone give me the answer

Mademuasel [1]

We want to begin with nine, which gives us as follows:

Then, we want to subtract:

9 -

And we are subtracting x:

9 - x

The expression is 9 - x for the steps in the image given.

Hope this helps!! :)

5 0

3 years ago

The point P=\left(-\frac{\sqrt{33}}{7},\,\, y\right)P=(− 7 33 ,y) lies on the unit circle shown below. What is the value of

kifflom [539]

Answer:

y = √-1040/7

Step-by-step explanation:

The equation of a unit circle is expressed as;

x²+y² = 1

Given the coordinate of P = (-33/7, y)

Substitute the coordinate into the give expression and find y;

(-33/7)²+y² = 1

Expand

y² = 1-(-33/7)²

According to difference of two square

y² = (1+(-33/7))1-(-33/7))

y² = (1-33/7)(1+33/7)

y² = -26/7(40/7)

y² = -1040/49

y= √-1040/49

y = √-1040/√49

y = √-1040/7

Hence the value of y is y = √-1040/7

4 0

2 years ago