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fredd [130]
3 years ago
7

Someone help me ASAP

Mathematics
2 answers:
Alex777 [14]3 years ago
7 0

Answer:

Volume=192

Step-by-step explanation:

Gelneren [198K]3 years ago
6 0

Answer:

Surface area: 208 inches

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Frankie descends 56 ft in 4 minutes. what is frankies average change in position per minute from which he started.
ArbitrLikvidat [17]

Answer:

14?

Step-by-step explanation:

6 0
3 years ago
City A is 10 miles from city B and 5 miles from city C. Cities A, B, and C form a right triangle at A. A road connects cities B
laila [671]

Answer:

11.18 miles

Step-by-step explanation:

The sides of a right triangle a, b, c are related by the equation

a^2 + b^2 = c^2

where c is the longest side of the triangle

Hence given that A connects B and C directly and forms a right angle at A

5^2 + 10^2 = c^2

Where c is the length of the road

25 + 100 = c^2

125 = c^2

c = 125^1/2

= 11.18 miles

3 0
2 years ago
Describe two to evaluate 37% of the sum of 27 and 3/5 and 15.9
zhuklara [117]
First way is to first find the sum and then find 37% of it. Second way is another way round, find 37 of 27 3/5 and 37% of 15.9 and then add it.

Lets do it
37%=0.37
- its the result
Second way its
0.37* 27 3/5 + 0.37*15.9=10.212 + 5.888=16.095
7 0
3 years ago
A dance school has 54 students who learn salsa
Archy [21]

They should be 54 students who know how to salsa

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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