Answer: 5/6
Step-by-step explanation: trust me on this
Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.
Thus, the length of fencing needed is given by
P = x + 2y
The area of the rectangle is given by xy,
i.e.
![xy = 288 \\ \\ \\ \\ \Rightarrow y= \frac{288}{x}](https://tex.z-dn.net/?f=xy%20%3D%20288%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20y%3D%20%5Cfrac%7B288%7D%7Bx%7D%20)
Substituting for y into the equation for the length of fencing needed, we have
![P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}](https://tex.z-dn.net/?f=P%3Dx%2B2%5Cleft%28%20%5Cfrac%7B288%7D%7Bx%7D%20%5Cright%29%3Dx%2B%20%5Cfrac%7B576%7D%7Bx%7D%20)
For the amount of fencing to be minimum, then
![\frac{dP}{dx} =0 \\ \\ \Rightarrow1- \frac{576}{x^2} =0 \\ \\ \Rightarrow \frac{576}{x^2} =1 \\ \\ \Rightarrow x^2=576 \\ \\ \Rightarrow x=\sqrt{576}=24](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdx%7D%20%3D0%20%5C%5C%20%20%5C%5C%20%5CRightarrow1-%20%5Cfrac%7B576%7D%7Bx%5E2%7D%20%3D0%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20%5Cfrac%7B576%7D%7Bx%5E2%7D%20%3D1%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20x%5E2%3D576%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20x%3D%5Csqrt%7B576%7D%3D24)
Now, recall that
![y= \frac{288}{x} = \frac{288}{24} =12](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B288%7D%7Bx%7D%20%3D%20%5Cfrac%7B288%7D%7B24%7D%20%3D12)
Thus, the length of fencing needed is given by
P = x + 2y = 24 + 2(12) = 24 + 24 = 48.
Therefore, 48 feets of fencing is needed to enclose the garden.
Answer:
degrees and the measure of angle 5 is -------- degrees. The measure of angl
Step-by-step explanation:
Answer:
(a). 15
(b). 78
Step-by-step explanation:
Growth of the population of a fruit fly is modeled by
N(t) = ![\frac{600}{1+39e^{-0.16t} }](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B39e%5E%7B-0.16t%7D%20%7D)
where t = number of days from the beginning of the experiment.
(a). For t = 0 [Initial population]
N(0) = ![\frac{600}{1+39e^{-0.16\times 0} }](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B39e%5E%7B-0.16%5Ctimes%200%7D%20%7D)
= ![\frac{600}{1+39}](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B39%7D)
= ![\frac{600}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B40%7D)
= 15
Initial population of the fruit flies were 15.
(b).Population of the fruit fly colony on 11th day.
N(11) = ![\frac{600}{1+39e^{-0.16\times 11} }](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B39e%5E%7B-0.16%5Ctimes%2011%7D%20%7D)
= ![\frac{600}{1+39e^{-1.76} }](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B39e%5E%7B-1.76%7D%20%7D)
= ![\frac{600}{1+39\times 0.172 }](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B39%5Ctimes%200.172%20%7D)
= ![\frac{600}{1+6.71}](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B1%2B6.71%7D)
= ![\frac{600}{7.71}](https://tex.z-dn.net/?f=%5Cfrac%7B600%7D%7B7.71%7D)
= 77.82
≈ 78
On 11th day number of fruit flies colony were 78.