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3 years ago

What's 1e?I need to solve this issue!

1 answer:

5 0

It means 1*10^+a number
for example:
1e*10^+11
the +11 is an exponent but with a plus sign

furthering the answer you'll get: 100000000000

You might be interested in

Please help, the brainiest will go to the one with a good answer.

Mashutka [201]

Option c is your answer 3xy + 7x4

3 0

2 years ago

The lifespans of gorillas in a particular zoo are normally distributed. The average gorilla lives 20.8 years; the

Luda [366]

If the mean is 20.8, one standard deviation each way is adding and subtracting 3.1, so 17.7 and 23.9 (68% of values)

Two standard deviations adding and subtracting 3.1*2 = 6.2, or 14.6 and 27.

Three standard deviations is 11.5 and 30.1

So we have
11.5 - 14.6 - 17.7 - 20.8 - 23.9 - 27 - 30.1

Going left to 11.5 is 3 standard deviations out, so 99.7/2 = 49.85%

Going right to 27 is 2 standard deviations out, so 95/2 = 47.5%

Add those two % to get 97.32%

This is hard to do without a picture so I hope that helps!

3 0

2 years ago

Estimate using a rate per 100 of 74% of 315. 89% of 195

LiRa [457]

1. Given numbers:
74 % of 315
89% of 195

now, let’s solve the first given numbers:
=> 74% of 315
=> 315 is the 100%
Let’s convert 74% into decimals
=> 74% = .74
=> 315 * .74 = 233.1, the value of 74% of 315
Let’s solve the second given:
=> 89% of 195
where 195 is the 100%
=> 89% = .89
=> 195 * .89
=> 173.55, the value of 89% of 195

3 0

3 years ago

Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

2 years ago

Find the value of the variable and MN if N is between M and Q. Round to the nearest hundredth if necessary.

Rudiy27

Answer:
MN = 4 units

Explanation:
1- getting the value of m:
We are given that:
NQ = 4m and NQ = 12
This means that:
12 = 4m
$\frac{4m}{4} = \frac{12}{4}$
m = 3

2- getting MQ:
We are given that:
MQ = 5m + 1
We have calculated that:
m = 3
Therefore:
MQ = 5(3) + 1 = 15 + 1 = 16 units

3- getting MN:
We are given that point N is located somewhere between points M and Q.
This means that:
line MQ can be divided into two portions: MN and NQ
This also means that:
length of MQ = length of MN + length of NQ

We have calculated that:
MQ = 16 units
We are given that:
NQ = 12 units
Therefore:
16 = length of MN + 12
length of MN = 16 - 12
length of MN = 4 units

Hope this helps :)

3 0

2 years ago