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The range of a function is the set of possible values that can be obtained from the dependent variable. The range of the function is: $R: (500, \infty)$

Given that:

$Phone = \$500$

$Monthly\ Plan = \$60$

Let the number of months be t. So, the function C(t) is calculated as follows:

$C(t) = Phone + Monthly\ Plan \times t$

$C(t) = 500 + 60 \times t$

$C(t) = 500 + 60t$

The range is calculated as follows:

The smallest possible value of t is 0 i.e. when no monthly subscription is done.

So, we have:

$C(0) = 500 + 60\times 0= 500 + 0 = 500$

And the highest is $\infty$ i.e. for a large value of t

So, we have:

$C(\infty) = 500 + 60\times \infty= 500 + \infty = \infty$

Hence, the range of the function is:

$R: (500, \infty)$

Read more about range of functions at:

brainly.com/question/13824428

5 0

2 years ago

News article reports that "Americans have differing views on two potentially inconvenient and invasive practices that airports c

OverLord2011 [107]

Answer:

1) p1=0.83

2) p2=0.81

3) Option B

4) p=0.82

5) s=0.03

6) z=0.67

7) P=0.50

8) Do not reject H0

Step-by-step explanation:

1) The proportion of Republicans who think the full-body scans should be applied in airports is equal to the ratio between the republicans that think it should over the total Republicans in the poll:

$p=X/n=258/311=0.83$

2) The proportion of Democrats who think the full-body scans should be applied in airports is equal to:

$p=X/n=294/363=0.81$

3) As we want to know if there is a difference in the proportions calculated, not if one is higher or lower than the other, the correct option is B:

$H_0:p_1-p_2=0\\\\H_a:p_1-p_2\neq0$

4) The pooled estimate of a proportion is the average of both proportions:

$\bar{p}=\frac{p_1+p_2}{2}= \frac{0.83+0.81}{2}=0.82$

5) The standard error can be calculated as:

$s=\sqrt{\frac{\bar{p}(1-\bar{p})}{n_1} +\frac{\bar{p}(1-\bar{p})}{n_2}} \\\\s=\sqrt{\frac{0.82*0.18}{311} +\frac{0.82*0.18}{363}} \\\\s=\sqrt{0.00047+0.00041} =\sqrt{0.00088}=0.03$

6) The z-statistic can be calculated as:

$z=\frac{p_1-p_2}{s}=\frac{0.83-0.81}{0.03}=\frac{0.02}{0.03}=0.67$

7) The P-value for z=0.67 is P=0.50 (from the standard normal distribution table).

$2P(Z>|z|)=0.50286$

8) If the significance level is 0.01, the P-value is bigger than the significance level. The effect is not significanct. The null hypothesis is not rejected.

There is not enough evidence to say that both proportions are different.

A. Do not reject H0

8 0

2 years ago

PLEASE HELP GIVE BRANLIEST!!

Ipatiy [6.2K]

Answer:

1. 2/25

2. 4/15

Step-by-step explanation:

1. P(Y∩X)

Since P(X) =2/3 , P(Y) =2/5 , and P(X|Y) =1/5, this is a conditional probability.

So P(Y∩X) = P(Y)P(X|Y) = 2/5 × 1/5 = 2/25

2. P(Y)· P(X)

P(Y)· P(X) = 2/3 × 2/5 = 4/15

7 0

3 years ago