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Eva8 [605]
4 years ago
8

True or False cos^2x=(1-cos2x)/2

Mathematics
2 answers:
marin [14]4 years ago
6 0

Answer:

False

Step-by-step explanation:

From the trigonometric identity: cos(x+y) = cos(x)*cos(y) - sin(x)*sin(y) we can get:

cos(x+y) = cos(x)*cos(y) - sin(x)*sin(y)

cos(x+x) = cos(x)*cos(x) - sin(x)*sin(x)

cos(2x) = cos^2(x) - sin^2(x)

cos^2(x) = cos(2x) + sin^2(x) (eq. 1)

From the trigonometric identity: cos^2(x) + sin^2(x) =1 we can get:

cos^2(x) + sin^2(x) = 1

sin^2(x) = 1 - cos^2(x) (eq. 2)

Replacing equation (1) into equation (2) we get:

cos^2(x) = cos(2x) + 1 - cos^2(x)

cos^2(x) + cos^2(x)  = 1 + cos(2x)

2*cos^2(x)  = 1 + cos(2x)

cos^2(x) = [1+cos(2x)]/2

love history [14]4 years ago
5 0

False

(My answer on Apex was correct)

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3 years ago
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WINSTONCH [101]

Answer:

x = 4

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Step-by-step explanation:

y = -2x + 1

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4 years ago
Translate into an algebraic expression: n−1 increased by 110%
lorasvet [3.4K]

Answer:

Part 1) The algebraic expression is equal to 1.10(n-1)  or 1.10n-1.10

Part 2) The algebraic expression is equal to \frac{1.10}{n}

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

1.10(n-1)

Distributed

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Part 2) we have n^(-1) increased by 110%

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Remember that

n^{-1}=\frac{1}{n}

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1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}

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Step-by-step explanation:

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