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3 years ago

13

What is the standard for 600,000+80,000+10

2 answers:

Angelina_Jolie [31]3 years ago

8 0

680,010 is the same 600,000+80,000+10

dimulka [17.4K]3 years ago

6 0

The standard form for 600,000 + 80,000 + 10 is 680,000

The standard form of any number is the number only using the numbers 0-9. And in this case, it is the sum of the numbers.

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Do these numbers 19.657 < 19.67

nexus9112 [7]

I dont understand your question.......

5 0

3 years ago

Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t

LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

$(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)$

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

$(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)$

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6) $=\dfrac{20}{36}$

The probability distribution of this event is given as follows.

$\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|$

First, we determine the expected Value of this event.

Expected Value

$=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67$

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning $=\dfrac{20}{36}$

If the game is played 100 times

Number of times expected to win

$=\dfrac{20}{36} \times 100\\=56$ times$

Therefore, number of times expected to loose

= 100-56

=44 times

8 0

3 years ago

Valerie deposits $1,900 in an account that

horrorfan [7]

Answer:

$2273.19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Compound Interest Rate Formula: $\displaystyle A = P(1 + \frac{r}{n})^{nt}$

A is final amount
P is principle amount
r is rate
n is compound rate
t is time (in years)

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

P = $1900

r = 3% = 0.03

n = 4

<u>Step 2: Solve for </u><em><u>A</u></em>

Substitute [CIRF]: $\displaystyle A = 1900(1 + \frac{0.03}{4})^{4(6)}$
(Parenthesis) Divide: $\displaystyle A = 1900(1 + 0.0075)^{4(6)}$
(Parenthesis) Add: $\displaystyle A = 1900(1.0075)^{4(6)}$
(Exponents) Multiply: $\displaystyle A = 1900(1.0075)^{24}$
Exponents: $\displaystyle A = 1900(1.19641)$
Multiply: $\displaystyle A = 2273.19$

5 0

2 years ago

Please help!! Thank You I'll give you BRIANLEIST!! :D ^ ^

RSB [31]

Answer:

False

Step-by-step explanation:

SO SO SO SO SO SO SO sry if this is wrong!!!! i'm 99.9 persecnt sure its right!!!! :):)::)

5 0

3 years ago

Simplify x^2-9/x^2+x-12

Serjik [45]

Answer: \frac{x+3}{x+4}

Step-by-step explanation:

\frac{x^2-9}{x^2+x-12}

\frac{(x+3)(x-3)}{(x+4)(x-3)} =\frac{x+3}{x+4}

8 0

3 years ago

Read 2 more answers