Find the slope of the line passing through the points (-7, -3) and (6,-3
1 answer:
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Answer:
see explanation
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
Answer: 346.4
Step-by-step explanation:
The whole triangle ABD is a 30-60-90 right triangle. In 30-60-90 triangles, the smallest side is x, the middle side is x, and the largest side/hypotenuse is 2x.
Side AB is the smallest side and therefore x=300. Side BD is the middle side and so we can use x and we get BD=300
=519.615
The question is asking for CD, and we know that CD can be equal to BD minus BC since that would isolate CD
Triangle ABC is also a 30-60-90 triangle but the 300 feet is the middle side in this triangle. So we can do 300=x and divide 300 by radical 3 and get that x=173.205
Side BC is the smallest side of this triangle so it would be x and x is 173.205.
Now that we have the whole side BD and the part of it BC. We can subtract BD by BC (519.615-173.205) and we get that CD=346.4