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Ratling [72]
2 years ago
12

Which of the following cross sections cannot be produced by slicing a right rectangular prism? A. pentagon B. circle C. rectangl

e D. trapezoid
Mathematics
2 answers:
Lina20 [59]2 years ago
6 0

Answer: B. Circle

Step-by-step explanation:

Since the base is a rectangle and the faces are rectangular, there is no way to slice the prism to get a a circle.

The trapezoid ? Maybe. A diagonal slice starting on a corner will create a quadrilateral with uneven sides.

Pentagon? Imagine starting on the top near a corner-- but not on the corner-- with a diagonal line, slicing down towards the opposite corner. You should be able to get an irregular pentagon.

A rectangle is easy!

No circles!

Enjoy! I hope this helps you.

lys-0071 [83]2 years ago
3 0

Answer:

The answer is option B.

Step-by-step explanation:

Since it's a rectangular prism slicing will produce either a rectangle or trapezoid and not or a circle since it's round

Hope this helps you

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Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4).
xenn [34]

Intercept form is: y = a(x - p)(x - q)  

It is given that:  p = 14, q = -6, x = 14, y = 4

4 = a(14 - 12)(14 - (-6))

4 = a(2)(20)

4 = 40a

\frac{4}{40} = \frac{40a}{40}

\frac{1}{10} = a

Answer: y = \frac{1}{10}(x - 14)(x + 6)



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Answer:

5

Step-by-step explanation:

x × 4 = x + 15

4x = x + 15

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Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method
antoniya [11.8K]

Answer:

a

The estimate is  - 0.0265\le  K \le  0.0465

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is  n_1 = 400

The number of faulty breaks of method A is  X_1 = 32

 The number of microchips broken in method B is  n_2  = 400

 The number of faulty breaks of method A is  X_2 = 32

  The proportion of the faulty breaks to the total breaks in method A is

       p_1 = \frac{32}{400}

      p_1 = 0.08

 The proportion of the faulty to the total breaks in method B is

      p_2 =  \frac{28}{400}

     p_2 =  0.07

For this estimation the standard error is  

      SE =  \sqrt{ \frac{p_1 (1 - p_1)}{n_1}  + \frac{p_2 (1- p_2 )}{n_2} } }

  substituting values

       SE =  \sqrt{ \frac{0.08 (1 - 0.08)}{400}  + \frac{0.07 (1- 0.07 )}{400} } }

      SE = 0.0186

The z-values of confidence coefficient of 0.95 from the z-table is  

       z_{0.95} =  1.96

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

        K = [p_1 - p_2 ] \pm z_{0.95} * SE

substituting values

        K = [0.08 - 0.07 ] \pm 1.96 *0.0186

         K  =  - 0.0265 \ or  \ K  =  0.0465

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is  

      - 0.0265\le  K \le  0.0465

3 0
2 years ago
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