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Sauron [17]
2 years ago
7

Base area:12.5m^2;height:1.2m

Mathematics
1 answer:
lilavasa [31]2 years ago
8 0
? Ummm What is the question???
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HELP PLEASEEEEEEEEE.........!!!!!!!!!!!!!!!!​
den301095 [7]

Answer:

x = 65

Step-by-step explanation:

Angles are equal because of the vertical angle thm

2x + 15 = 145

2x = 130

x = 65

7 0
2 years ago
Which expression is equivalent to 64x^3-343
In-s [12.5K]

Answer:

B:  (4x - 7)(16x^2 + 28x + 49)

Step-by-step explanation:

64x^3-343 can be rewritten as 4^3x^3 - 7^3 or (4x)^3 - 7^3.  This is the difference of two cubes.  The appropriate formula for factoring such is

       a^3 - b^3 = (a - b)(a^2 + ab + b^2).  Therefore,

our (4x)^3 - 7^3 = (4x - 7)(16x^2 + 28x + 49).  This is Answer B.

4 0
3 years ago
Why do you think items that come in a larger quantity cost less per unit
MAXImum [283]
They cost less because there are more items in stock meaning that there isn't a limit here is another way of thinking if there are less Items then they can charge you more per item because they know you are gonna want it but if there are tons of that one item they there kinda like eh then you think oh I can live without that....... Hope this helps

7 0
2 years ago
Read 2 more answers
How do you simplify this problem
vampirchik [111]
Reduce the fraction with 2
\frac{2 \times x {}^{ - 2} y {}^{3}z {}^{ - 1}  }{xy}  \\  \\  \frac{3y {}^{2}z {}^{ - 1}  }{x {}^{3} }  \\  \\  \frac{3y {}^{2} }{x {}^{3}   z}
7 0
3 years ago
Which of the following correctly describes the domain of the function shown
labwork [276]

Option D:

\{x: x \neq 1\} is the domain of the function.

Solution:

Given function is

$r(x)=\frac{2 x}{x-1}

<u>To find the domain of the function:</u>

Option A: \{x: x \neq 0\}

Substitute x = 0 in r(x).

$r(0)=\frac{2 \times 0}{0-1}=0

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, \{x: x \neq 0\} is not the domain of the function.

Option B: \{x: x \neq \pm 1\}

Substitute x = –1 in r(x).

$r(-1)=\frac{2 \times (-1)}{-1-1}=1

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, \{x: x \neq \pm 1\} is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: \{x: x \neq 1\}

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, \{x: x \neq 1\} is the domain of the function.

4 0
3 years ago
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