All categories

3 years ago

Write an algebraic equation to match each graph. (These graphs are not drawn to scale!)

Mathematics

2 answers:

Anna11 [10]3 years ago

8 0

Answer:

y=|x+1|

Step-by-step explanation:

The y value appears to be 1 more than the x value, so we need to add one to the x to make them even. (x+1)

But the y value doesn’t go below zero, so we need to add the absolute value brackets |x+1|

So y=|x+1|

Vaselesa [24]3 years ago

3 0

Answer:

y=|x+1|

Step-by-step explanation:

You might be interested in

How to solve ×+6y=13. 2×+y=15

saul85 [17]

Answer:

x, y = 7, 1

Step-by-step explanation:

x+6y=13 ............ (i)

2x+y=15 ........... (ii)

We will apply substitute method.

From equation (i), we can get,

x+6y=13

or, x = 13 - 6y .......... (iii)

Putting the value of x in equation (ii), we can get,

2x+y=15

or, 2 × (13 - 6y) + y = 15

or, 26 - 12 y + y = 15 [multiplying]

or, -11 y = 15 - 26 [Subtracting 26 from both the sides]

or, -11 y = -11

or, [(-11 y) ÷ (-11)] = [(-11) ÷ (-11)] [Dividing both the sides by -11]

or, y = 1

Therefore, the value of y = 1

Putting y = 1 in equation (iii), we get,

x = 13 - 6y

or, x = 13 - 6 × 1

or, x = 13 - 6

or, x = 7

Therefore, the value of x = 7.

Answer: x, y = 7, 1

3 0

3 years ago

Find (−18)+(−25)+13 . −56 −30 20 −6

timama [110]

Answer:

Step-by-step explanation:

-18 + (-25) + 13 =

-18 - 25 + 13 =

-43 + 13 =

-30 <====

7 0

4 years ago

A credit card bill for $559 was due on September 14. Purchases of $289 were made on September 19, and $15 was charged on Septemb

Sunny_sXe [5.5K]

Answer: $623

Step-by-step explanation:

calculation of Finance charge due on October 14

(+) $ 559 due on sep 14, $ 559 * (19.5*31) / (100 * 365) = $ 9.20

(+) purchase $ 289 on sep 19, $ 289 * (19.5*26 ) / (100 * 365) = $ 2.42

(+) finance charge on sep 28, $ 18 *(19.5*17 ) / (100 * 365) = $ 0.17

(-) Repayment on 25 sep , $ 250 * (19.5*20 ) / (100 * 365) = (2.745)

Total finance charges from 14 sep to 14 oct = $ 9.7= appr. 10

Amount due on 14 October = $559+$289+$15+$11.855- $250

= $ 623

3 0

4 years ago

Y=(6+3X)^2/3 Find the derivative of the function using the chain rule

fomenos

$\bf y=(6+3x)^{\frac{2}{3}}\implies \cfrac{dy}{dx}=\stackrel{chain~rule}{\cfrac{2}{3}(6+3x)^{\frac{2}{3}-1}\cdot (0+3)}
\\\\\\
\cfrac{dy}{dx}=\cfrac{2}{3}(6+3x)^{-\frac{1}{3}}\cdot 3\implies \cfrac{dy}{dx}=2(6+3x)^{-\frac{1}{3}}\implies \cfrac{dy}{dx}=\cfrac{2}{\sqrt[3]{6+3x}}$

5 0

4 years ago

The first five multiples for the numbers 4 and 6

exis [7]

Answer:

4: 4,8,12,16,20

6: 6,12,18,24,30

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers