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3 years ago

Identify the shape. A. Trapezoid B. Rectangle C. Rhombus D. Square

2 answers:

8 0

The questions answer is inconclusive due to shape being not displayed. All of them are quadrilaterals but that's about all I can tell you until you display the desired, unidentified shape. Sorry. :(

Anna11 [10]3 years ago

5 0

the answer is C

Rhombus for pf test

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The bar graph shows how each month's rainfall compares to the historical average.

mina [271]

Answer:

a. The difference in rainfall is 4.03in

b. The total amount of rainfall for the year is negative, -1.73

Step-by-step explanation:

a. Wettest month 2.36in and dryest month -1.67in

2.36

-1.67

-------

4.03

b. -0.45 + -0.88 + 0.94 + -1.67 + -0.96 + 0.83 + 2.36 + 1.39 + 0.35 + -1.35 + -0.9 + -1.39 = -1.73

3 0

3 years ago

Scott walks to and from school each day. Each round trip is 3 kilometers long.

natka813 [3]

The equation that shows the relationship between the number of round trips, x and the number of kilometers, y Scott walked is y = 3x

Each round trip = 3 km

x = number of rounds

y = number of km he has walked in all.

1 rounds = 3 km

Therefore,

x rounds = 3x km

Each round of trip covers 3km. This means for each round of trip a distance of 3km is covered. The total distance or number of kilometers is represented with y.

The equation to show the relationship between x(number of rounds) and y (number of km) can be represented below

y = 3x

8 0

3 years ago

This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is

BaLLatris [955]

Answer:

$\frac{r}{3\pi h+r}$

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

$A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}$

Now, area of 2 cylinders would be the formula:

$A_{cyl}=2*(\pi r^2 h)=2\pi r^2 h$

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm divided by A_total.

Shown below:

$\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}$

We simplify further:

$\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}$