All categories

3 years ago

What is the range of f(x)=x^3

Mathematics

2 answers:

siniylev [52]3 years ago

5 0

Answer:

all positive real numbers

Alecsey [184]3 years ago

3 0

Infinity because it's a cubic function with no restricted range or domain

You might be interested in

Triangle DEF has coordinates D(1,1). E(1,5), and F(5.1). Triangle D'EF is the image of ADEF by a dilation with center (0.0) and

Nastasia [14]

Answer:

$2282 \div 2 = < \leqslant 2 \times \frac{?}{?} {?}^{?} \sqrt{226 \tan( \cot(?) ) }$

5 0

3 years ago

Find the slope of the line. pleaseee

Akimi4 [234]

Answer:

Step-by-step explanation:

The slope is the change in y divided by the corresponding change in x:

∆y/∆x = (54.99 -54.99)/(7 -6) = 0/1 = 0

The slope of the line is zero.

7 0

3 years ago

An avid traveler is investigating whether travel websites differ in their pricing. She chooses a random sample of 32 hotel rooms

Tatiana [17]

The answer is D beachside trust

8 0

2 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

so the final answer is

$(3x-2)^2$

5 0

2 years ago

Which one does not belong and why

Sliva [168]

Answer:

The Circle on the Top right doesn't belong since every other circle has a green quadrant, whereas on the other hand the circle on top right is missing the green quadrant

Hope this helps!

7 0

3 years ago