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marysya [2.9K]
3 years ago
11

−18 ÷ 6 − 8 = need help ASAP

Mathematics
2 answers:
7nadin3 [17]3 years ago
7 0

Answer: -11

Step-by-step explanation: trust me

Olenka [21]3 years ago
3 0

Step-by-step explanation:

-18÷6-8

-3-8=-11 is the answer

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A florist is making blue and white flower arrangements for the arrangements he places a red ribbon on every third Arrangement an
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The Arrangement that will be the first to have a red and blue ribbon is the 15th arrangement.

<h3>What is LCM?</h3>

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

Given the florist places a red ribbon on every third Arrangement and a blue ribbon on every fifth Arrangement. Therefore, to find the arrangement that will have both a red and a blue ribbon, you need to take the LCM of 3 and 5.

Since the LCM is 15, therefore, the Arrangement that will be the first to have a red and blue ribbon is the 15th arrangement.

Learn more about Least Common Multiple:

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7 0
2 years ago
4. From the given geometrical terms<br>which one is odd? a) S.S.S b) A.A.A c)r.h.s<br>b)<br>d)s.a.s​
Kryger [21]

Answer:

AAA

Step-by-step explanation:

The answer is AAA because the other choices are all triangle congruence properties. However, AAA is not a triangle congruence property, hence, it is the odd one out. SSS stands for Side - Side - Side, AAA stands for Angle - Angle - Angle, RHS stands for Right Angle - Hypotenuse - Side and SAS stands for Side - Angle - Side.

6 0
3 years ago
For everyone out there just dont do it
quester [9]

Answer:

thank you i needed that

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How many solutions does tan^-1 3 have in interval [0, 2 π)
zhuklara [117]
\bf tan^{-1}(3)\iff tan^{-1}\left( \frac{\pm 3}{\pm 1} \right)=\theta&#10;\\\\\\&#10;thus\qquad tan(\theta)=\cfrac{\pm 3}{\pm 1}\cfrac{\leftarrow opposite=y}{\leftarrow adjacent=x}

now, the angle of θ, can only have a "y" value that is positive on, well, y is positive at 1st and 2nd quadrants

and "x" is positive only in 1st and 4th quadrants

now, that angle θ, can only have those two fellows, "y" and "x" to be positive, only in the 1st quadrant, and also both to be negative on the 3rd quadrant.

and that those two fellows, can also be both negative in the 3rd quadrant
3/1 = 3, and -3/-1 = 3

so, the solutions can only be "3", when both "y" and "x" are the same sign, and that only occurs on the 1st and 3rd quadrants
6 0
3 years ago
X²+8x-84=0 <br><br>Formúla General ​
Brums [2.3K]

Answer:

                x_{1} =-14\\\\x_{2} =6

Step-by-step explanation:

x^{2} +8x-84=0\\\\x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=1; \: \: b=8; \: \: c=-84\\\\x=\dfrac{-8 \pm \sqrt{8^{2}-4 \cdot 1 \cdot (-84) } }{2 \cdot 1}=\dfrac{-8 \pm \sqrt{400 } }{2}=\dfrac{-8 \pm20}{2} =-4 \pm 10\\\\x_{1} =-14\\\\x_{2} =6

8 0
3 years ago
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