Question

As part of a physics experiment, Ming drops a baseball from the top of a 315-foot building. To the nearest tenth of a second, for how many seconds will the baseball fall? (Hint: Use the formula h = 16t^2, which gives the distance h, in feet, that a free-falling object travels in t seconds.)

Answer 1

Answer:  4.4 seconds

Step-by-step explanation:

h(t) = -16t² + 315

Since we want to find the total time the baseball is in the air, we need to find the time (t) when the ball lands on the ground --> h(t) = 0

  0  = -16t² + 315

-315 = -16t²

$\dfrac{315}{16}=t^2\\\\\\\sqrt{\dfrac{315}{16}}=t\\\\\\\dfrac{\sqrt{315}}{4}=t\\\\\\\large\boxed{4.4=t}$

Answer 2

Answer:

≈ 4.44 sec

Step-by-step explanation:

h= 315 ft

h= 16t²

315 = 16t²

t²=315/16

t=√315/16 ≈ 4.44 sec