Answer:
($2.123 ; $2.149)
Step-by-step explanation:
The prediction interval is expressed as :
Predicted value ± standard Error
Predicted value = $2.136
Standard Error = $0.013
Prediction interval :
Lower boundary = $2.136 - $0.013 = $2.123
Upper boundary = $2.136 + $0.013 = $2.149
($2.123 ; $2.149)
B.) The prediction interval provides a range for which the predicted value or price should fall Given a certain degree of probability. If the true value falls within this interval, then, our prediction would be deemed to have occurred not by chance.
Since the actual price within the predicted price interval, then I agree with the judge's Decison that the price was not artificially depressed.
First, we find the slope
(4,0)(0,-3)
slope = (-3 - 0) / (0 - 4) = -3/-4 = 3/4
there can be 3 possible answers for this..
y - y1 = m(x - x1)
slope(m) = 3/4
using points (4,0)...x1 = 4 and y1 = 0
now we sub
y - 0 = 3/4(x - 4) <== this is one answer
y - y1 = m(x - x1)
slope(m) = 3/4
using points (0,-3)...x1 = 0 and y1 = -3
now we sub
y - (-3) = 3/4(x - 0) =
y + 3 = 3/4(x - 0) <== here is another answer
y - y1 = m(x - x1)
slope(m) = 3/4
using points (-4,-6)...x1 = -4 and y1 = -6
now we sub
y - (-6) = 3/4(x - (-4) =
y + 6 = 3/4(x + 4) <=== and here is another answer
Thank you for asking this question. Here is your answer:
M = y2 - y1/x2 - X1 = M
= 290 - 210/120 - 80
M = 80/40
M = 2
Now we will consider y intercept
y = mx + b
210 = 2(80) + b
210 = 160 + b
b = 210 - 160
= 50
Now we will combine everything in order to get the answer.
y = 2x + 50
y = 2(60) + 50
y = 120 + 50
y = 170
So the final answer for this question is $170.
If there is any confusion please leave a comment below.
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9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.