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3 years ago

Can you help me Its a test pls help

Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

It’s just 9 LOL yeahhhhhhhhhhhhhggg hope it goes well lollll

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Can someone please help me on this one?

hammer [34]

I think that the answer is a increase

3 0

3 years ago

Please help me find y

sertanlavr [38]

Answer:

Step-by-step explanation:

cos 60° = y / 10

y = 10 * 1/2 = 5

3 0

3 years ago

The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016

hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N( $\mu=4016 , \sigma^{2} = 532^{2}$ )

The standard normal z distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( $\frac{X-\mu}{\sigma}$ < $\frac{5026-4016}{532}$ ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

5 0

3 years ago

Tim has a rectangular prism with a length of 10 centimeters, a width of 2 centimeters, and an unknown height. he needs to build

ozzi

The volume of the original prism is given by:
V1 = (10) * (2) * (h)
rewriting:
V1 = 20h
Where,
h: height
The volume of the second prism is given by:
V2 = (5) * (w) * (h)
We know that the height is the same.
As the volume is the same then:
(5) * (w) * (h) = 20h
Clearing w we have:
w = (20/5) = 4 cm
Answer:
The width, in centimeters, of the new prism is:
w = 4cm

4 0

3 years ago

Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a

rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that $\sigma = 2$

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when $M = 0.5$ . So