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3 years ago

What is the average walking rate in miles per hour if the distance(miles)=0.5. And the Time (min)= 12

1 answer:

5 0

So in order for us to know the average walking rate in miles per hour, we have to convert 12 minutes to hours first. So 12 minutes is 0.2 hours. So the rate is 0.5 miles in 0.2 hours. But since the question is the rate per hour, so the answer would be 2.5 miles/hour. Hope this answers your question.

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What are 6 whole numbers -3.5 and 5.5

Blababa [14]

Answer:

$This is a long long title restart$

3 0

3 years ago

2. Graph the function y=x^2+2x-3 . Draw a chart to show at least three ordered pairs that are on the graph.

lidiya [134]

You'd have to draw a table of x and y values first to be able to graph.
Step 1: Pick any number for x. Let's pick 2.
Step 2: Plug in 2 into the equation: y = 2^2 + 2(2) - 3
Step 3: Solve for y: 4 + 4 - 3 = 5
Step 4: So the point (ordered pair) would be (x, y) ⇒ (2, 5). You can plot that on the graph.

Follow these steps 2 more times to get at least three ordered pairs.

Make sure you have enough points to know where the graph curves, then you can connect the dots and now there you have a graph and chart :)

6 0

3 years ago

an artist is using tiles and boards for a project. A tile has length 2/3 ft and width 2/3 ft. A board has length 1/2 yd and widt

Margaret [11]

Answer:

4 : 9

Step-by-step explanation:

The requested ratio is ...

tile length : board length = (2/3 ft) : (1/2 yd) = (8 in) : (18 in)

= 8 : 18 = 4 : 9

_____

To make a unitless ratio, both parts must have the same units. Here, we chose to express the lengths in inches. We could have used feet or yards as well. (2/3 ft)×(1 yard)/(3 ft) = 2/9 yd or (1/2 yd)(3 ft/yd) = 3/2 ft. You get the same ratio with any of these:

(2/9 yd) : (1/2 yd) = (4 yd) : (9 yd) = 4 : 9 . . . . . multiply by 18

(2/3 ft) : (3/2 ft) = (4 ft) : (9 ft) = 4 : 9 . . . . . multiply by 6

5 0

3 years ago

Explain how to graph the in inequality 8>y

insens350 [35]

Answer:

How to Graph a Linear Inequality

First, graph the "equals" line, then shade in the correct area.

There are three steps:

1.) Rearrange the equation so "y" is on the left and everything else on the right.

2.) Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

4.) Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).

Hope This Helps! Have A Nice Day!!

8 0

3 years ago

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago