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Cloud [144]
3 years ago
10

1. Anike needs a new pair of athletic shoes for her soccer tryouts. The regular price for the shoes is $129.00. There is a sales

tax of 7%. Anike has a budget of $150.00. How much money will Anike have left after this purchase? Round to the nearest cent, like $7.15.
50−(129+129(0.07))=$11.97
129+129(0.07)=$138.03
150+129(0.07)=$140.97
150−(129+150(0.07)=$10.50

2. Harper has budgeted $525 to purchase a new laptop. She found one on sale for $500, and the sales tax is 6.25% in her state. How much will she actually have to pay for the laptop?

$31.25
$531.25
$468.75
$500.00

3. Mr. Robinson is planning to buy a house with the appraised value of $250,000. The property tax rate is 37.658. What are his yearly property tax fees?

$9314.00
$9314.50
$9414.50
$9400.15


PLEASE HELP IM JUST TRYING TO GET PASSED FINANCIAL MATH D:
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

$150-$129-($129*7%)=$11.97

$531.25

$9414.5

Step-by-step explanation:

The amount that Anike would have left is the budgeted amount minus the regular price as well as the applicable sales tax.

Amount left=$150-$129-($129*7%)=$11.97

The amount that Harper would have to pay is the purchase price of $500 plus the 6.25% of sales price as sales tax i.e $500+$500*6.25%=$531.25

The yearly tax fees is the appraised value multiplied by property tax rate i.e $250,000*3.7658%=$9414.5

The property tax rate is 3.7658% not 37.658%

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Answer:

Let

x=sin-¹u

Sinx=u

let y=tan-¹v

tany=v

Substituting

Sin[x + y]

Applying the sine expansion

Sinxcosy + CosxSiny

Recall x =Sin-¹u

y=tan-¹v

Sin(Sin-¹u)Cos(tan-¹v) +Cos(sin-¹u)Sin(tan-¹v)

Now at this point

Here's what you do

For the first expression

Sin(Sin-¹u)

Let's simplify this

Let P = Sin-¹u

Taking sine of both sides

SinP=u

Draw a Right angled angle for this

Since Sine from SOHCAHTOA is OPP/HYP

Where P is the angle and u is the opposite and 1 is the hypotenuse since u is the same as u/1

substituting Sin-¹u = P

You have

Sin(Sin-¹u) = SinP

and from the triangle you drew

SinP = u

Taking the second express

Cos(tan-¹v)

Let Q=Tan-¹v

taking tan of both sides

tanQ=v

Draw a right angled triangle for this too

Since Tan from SOHCAHTOA is OPP/ADJ

Find the Hypotenuse cos you'll need it

Now Let's do the substitution again

We first said tan-¹v = Q

When we substitute it in Cos(tan-¹v)

We have CosQ

Cos Q from the second right angle triangle you drew is 1/√1+v²

Because CAH is adj/Hyp

So

the first part of the original Express

Which is

Sin(Sin-¹u)Cos(tan-¹v) is now simplified to

u(1/√1+v²).

Let's Move to the second part of the Original Expression

Cos(Sin-¹u)Sin(tan-¹v)

From our first solution

We said Sin-¹u= P

So replacing it here

we have Cos(sin-¹u) = CosP

let's leave the second one for now which is sin(tan-1v) We'll deal with this after the first

so Cos(Sin-¹u) = CosP

we can still use our first Right angle triangle for this because the angle was P.

so Cos P from that triangle will be

CosP= √1-u²

Now onto the next

Sin(tan-¹v)

From the Second solution of the first we did

we said let Tan-¹v =Q

Substituting this

we have

Sin(tan-¹v) = SinQ

using the second Right angle triangle because its angle is Q

We have

SinQ= v/√1+v²

Answer for second phase Which is

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We're done

compiling our answers

The answer to

Sin(Sin-¹u - tan-¹v) = u(1/√1+v²) + [(√1-u²)(v/√1+v²)]

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