Step-by-step explanation:
(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)
1/(8x⁵y^-7) = y⁷/(8x⁵)
4x^-9y⁴ = 4y⁴/x⁹
so, the whole expression is then
y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹
4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)
so, D is the correct answer.
Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
Answer:
this isn’t a 100% guaranteed correct answer but maybe the second option saying “PQ and P’G’ are parallel”
(i’m doing the test rn)
Answer:
mean = 2.55
Standard deviation = 1.118
Step-by-step explanation:
Probability of babies who are boys
P = 0.51
Then we have q = 1-p
= 1-0.51
= 0.49
We have n = 5
We calculate the mean as:
np
= 0.51x5
= 2.55
Therefore mean = 2.55
The standard deviation
= √variance
= √npq
= √0.51x5x0.49
=√1.2495
= 1.118
