Two figure in front

h=16+17 = 33 m
l=18 m
width = 13 m
Volume = lwh = 18*13*33 =7722 m^2

Two figures at the back

h=16 m
l=18+18 =36 m
width = 15 m

Volume = lwh =36*15*16 =8640 m^2

Total volume = 7722+8640 = 16362 m^2

5 0

3 years ago

Hector can fit 75 compact discs into 5 boxes. How many compact discs can he fit into 14 boxes?

Karolina [17]

Answer:

Hector can fit 210 compact discs into 14 boxes.

8 0

2 years ago

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays. Assuming the

AysviL [449]

Answer:

1.83% probability there are no car accidents on that stretch on Monday

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.

This means that $\mu = 4$

What is the probability there are no car accidents on that stretch on Monday?

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4}*(4)^{0}}{(0)!} = 0.0183$

1.83% probability there are no car accidents on that stretch on Monday

5 0

2 years ago