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3 years ago

What is the factorization of the

Mathematics

2 answers:

astra-53 [7]3 years ago

8 0

B is the correct answer. plz heart my answers, I solved multiple of your questions. I just wanna like for my answers

Varvara68 [4.7K]3 years ago

5 0

Answer:

its B

Step-by-step explanation:

the answer is B (×+3)(×+4)

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How can I learn to understand it more

Phantasy [73]

Step-by-step explanation:

Well if you dont understand something ask a teacher for help or study on a topic that you struggle with for example math try looking up different math questions and solving them or ask a teacher is you can have pratice questions or problems then show it to him/her so they can check to see if you are right. Hope that help unless you dont understand a certain question that I might have missed.

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3 years ago

A _____________________________ has a constant change in the x values and a constant ratio in the y values.

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3 years ago

What is y=4/5x+2 written in standard form

shepuryov [24]

Answer:

$4x-5y=-10$

Step-by-step explanation:

we know that

The equation of the line in standard form is in the form

$Ax + By = C$

where

A is a positive integer, and B, and C are integers

In this problem we have

$y=\frac{4}{5}x+2$ ----> equation of the line in slope intercept form

Convert to standard form

Multiply by 5 both sides

$5y=4x+10$

$4x-5y=-10$

5 0

3 years ago

Read 2 more answers

A weather forecaster says the temperature will be about -5C “give or take” 10 degrees. What is the greatest possible temperature

bagirrra123 [75]

Minimum: -15C

Max: 5C

4 0

2 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

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3 years ago