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marusya05 [52]
3 years ago
12

I need help with one of these 2 questions.

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

I don’t know the first one but the second one is C

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Hi there! Here is to help your math homework
vfiekz [6]

Answer:

<h2> TYSM </h2>

I'LL DOWNLOAD AND THANK YOU LATER.

8 0
4 years ago
I need help plz and plz explain why plz
Mariana [72]

Answer:

156 minutes

Step-by-step explanation:

2 hrs=120 minutes

3/5 hr=3/5 *60=36 minutes

120+36=156 minutes

hope this helps

brainliest?

6 0
3 years ago
Read 2 more answers
2 = -5x + (2y + 2x) in slope intercept form
Nonamiya [84]
Answer: y = 1.5x + 1

Step by step:
First, combine like terms then isolate the y value: -2y = -3x-2

Then divide both sides by -2 to get the answer.
6 0
3 years ago
Please help soon!
Jlenok [28]

Answer:

a) Translate the graph of f(x) down 3 units.

b) (8,-1) is a point on the graph of g(x)

Step-by-step explanation:

The transformations that subtract a constant number of units from the functional expression f(x) are transformations that lower the graph of the function in those many units,

Therefore they correspond to a translation of the original graph down the number of units involved.

In this case, the number of units involved is "3" (due to the "-3" added to the expression for f(x). So he correct answer for the first part is: Translate the graph of f(x) down 3 units.

For the second part, one has to try each of the coordinate pairs given in the new function g(x) to see which one results in a true statement:

1) Testing (-8,-1) by checking if replacing x with the value "-8" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(-8)=\sqrt[3]{-8} -3\\g(-8)=-2-3\\g(-8)=-5

so this is NOT a point on the graph of g(x).

2) Testing (-1,-2) by checking if replacing x with the value "-1" renders "-2" for the y-value: g(x)=\sqrt[3]{x} -3\\g(-1)=\sqrt[3]{-1} -3\\g(-1)=-1-3\\g(-1)=-4

so this is NOT a point on the graph of g(x).

3) Testing (2,-1) by checking if replacing x with the value "2" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(2)=\sqrt[3]{2} -3\\

the cubic root of 2 is not a rational number, because 2 is not a perfect cube, so the expression cannot be reduced, so this is NOT a point on the graph of g(x).

4) Testing (8,-1) by checking if replacing x with the value "8" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(8)=\sqrt[3]{8} -3\\g(8)=2-3\\g(8)=-1

Therefore this pair (8,-1) IS a point on the graph of g(x).

5 0
3 years ago
Read 2 more answers
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
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