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IgorLugansk [536]
3 years ago
8

How do I write an equation that has variables on both sides and has a solution of -3

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0
I guess just work backwards. 
x=-3
2x=-6
x=-x-6

There ya go :P 
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Help help help pls NO links I can’t open them:( pic is above
Natali5045456 [20]

Answer:

a) 36°

b ) 18°

Step-by-step explanation:

The formula is given as:

The measure of each exterior angle =360°/n, where n = number of sides of a polygon.

a) decagon

Decagon = 10 sides

Hence, the measure of each exterior angle = 360°/10

= 36°

b) 20-gon

20-gon = 20 sides

Hence, the measure of each exterior angle = 360°/20

= 18°

8 0
2 years ago
Please help me with this homework
Agata [3.3K]

Answer:

-14.2, -7.8, 12.6, 15.3

Step-by-step explanation:

7 0
2 years ago
PLZ HELP
Zigmanuir [339]
I’m thinking 12. 5 times 12 is 60 which is divisible by 4 and 6. 1 times 12 is 12 which is divisible by 2. Hope that helps
8 0
2 years ago
Find the volume of given prism round to the nearest tenth necessary.
atroni [7]
First, find the area of the base (the triangle) and then multiply it by the height

to find the area of the triangle you need to know the height. cut the triangle in half and you get a right triangle, from there you can use the Pythagorean theorem. remember since you cut the triangle in half you have to divide one of the sides by 2

a^2 + b^2 = c^2              (plug in known information)
a^2 + (7.5)^2 = (15)^2      (solve, first solve the exponents)
a^2 + 56.25 = 225         (subtract 56.25 on both sides)
a^2 = 168.75                    (solve for a, put 168.75 under the square root)

then once you find the area multiply by the known height



7 0
2 years ago
If a coin is flipped 75 times, in how many ways could there be exactly two tails?
Dimas [21]

Answer:

2775 ways

Step-by-step explanation:

We have been given the case to choose exactly two tails when flipped 75 times  means  ^{75}C_2

Since, ^nC_r is equal to \frac{n!}{r!\cdot(n-r)!}  

Here n =75, r=2 substituting the values we will get

\frac{75!}{2!(75-2)!}

n!=n\cdot (n-1)\cdot (n-2).....1

After simplification we will get  \frac{75\cdot 74\cdot 73!}{2!\cdot73!}

Cancel out the common term that is 73! we will get

after more simplification we will get \frac{75\cdot 74\cdot}{2!}

Finally, we will get \frac{75\cdot 74\cdot}{2}=75\cdot37=2775

4 0
3 years ago
Read 2 more answers
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