Answer:
Wyzant
Question
Flying against the wind, an airplane travels 4200 km in 7 hours. Flying with the wind, the same plane travels 4000 km in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 1 vote
Let Va = the velocity of the airplane Let Vw = the velocity of the wind When flying with the wind: (Va+Vw)*(4 hours) = 4000 4Va + 4Vw = 4000 4Vw = 4000 - 4Va Vw = 1000 - Va When flying against the wind: (Va-Vw)*(7 hours) = 4200 km7Va - 7Vw = 4200 Substitute 1000-Va for Vw and solve for Va: 7Va - 7(1000-Va) = 4200 7Va -7000 + 7Va = 4200 14Va = 11200 Va = 800 km/hr Rate of wind: Vw = 1000 - Va = 1000 - 800 = 200 km/hour
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Socratic
Question
Flying against the wind, an airplane travels 4500 in 5 hours. Flying with the wind, the same plane travels 4640 in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 0 votes
The speed of plane in still air is 1030 km/hr and wind
Step-by-step explanation:
Answer:
(7v²-3)(v-4)
Step-by-step explanation:
Rewrite the expression by factoring out (v-4).
7v²(v - 4) – 3(v-4)
Since (v-4) is common to both terms, we only pick one of it to have a factored form:
(7v²-3)(v-4)
The new expression will be (7v²-3)(v-4)
To determine the length of time it would took for the biker to cool down, we need the rate that would relate the distance he traveled to cool down per units of time. For this problem, the rate is given as 0.25 miles per minute. So, we simply divide the total distance he traveled with this rate. We calculate as follows:
time to cool down = distance / rate
time to cool down = 35 miles / 0.25 miles / minute
time to cool down = 140 minutes or 2 hrs and 20 minutes
Therefore, the biker would need to cool down for about 2 hrs and 20 minutes if he traveled for 35 miles.
6x2 = 12
12 / 3 = 4 <span>6=6/1 so you do the numerators x the denominators which is 6x2/1x3=12/3 then simplify and make into a mixed number so final answer is 4</span>
Answer:
Thx have a great day :)
Step-by-step explanation:
