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Alja [10]
3 years ago
6

Can someone help me with the below question???

Mathematics
2 answers:
8_murik_8 [283]3 years ago
5 0

Answer:

so 2a+3b=±13

Step-by-step explanation:

4a²+9b²=97

ab=6

2a+3b=?

by using formula

(a+b)²=a²+b²+2ab

(2a+3b)²=(2a)²+(3b)²+2(2a)(3b)

(2a+3b)²=4a²+9b²+12ab

putting values

(2a+3b)²=97+12(6)

(2a+3b)²=97+72

(2a+3b)²=169

taking square root on both sides

√(2a+3b)²=√169

2a+3b=±13

i hope it will help you

Pie3 years ago
4 0

Answer:

2a+3b = 13

Step-by-step explanation:

<u><em>Using this formula</em></u>

(x+y)^2 = x^2+y^2+2xy

<u><em>Where,</em></u>

x = 2a and y = 3b

<u><em>Putting in the above formula</em></u>

=> (2a+3b)^2=4a^2+9b^2+12ab

Putting  4a²+9b² = 97 and ab = 6

=> (2a+3b)² = 97+12(6)

=> (2a+3b)² = 97+72

=> (2a+3b)² = 169

<em>Taking sqrt on both sides</em>

<em>=> </em><em>2a+3b = 13</em>

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The number of phone calls between two​ cities, N, during a given time period varies directly as the populations p 1 and p 2 of t
kherson [118]

Answer:

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

Step-by-step explanation:

Given that,

The number of phone calls between two cities (N )

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N\propto\frac{p_1p_2}{d}

N=k.\frac{p_1p_2}{d}

Given that,

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18,000=k.\frac{15,500\times 180,000}{310}

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\Rightarrow k=\frac{31}{15,500}

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N=? , d=435 miles,  p_1=100,500 and p_2=160,000

N=\frac{31}{15,500}.\frac{100,000\times 160,000}{435}

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5 0
3 years ago
Please help me thank you.
IrinaVladis [17]
I believe the answer is 1. hope that helped
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