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aksik [14]
4 years ago
13

How to graph -x+y< or equal to 5

Mathematics
1 answer:
muminat4 years ago
8 0

Answer:

  see below

Step-by-step explanation:

I find it convenient to use a graphing calculator to show the graph of many expressions, equations, and inequalities. See below for a graph.

__

If you want to graph this by hand, it is convenient to start by graphing the "equal to" case, the line ...

  -x + y = 5

or

  y = x + 5

This is a line with a slope of +1 and a y-intercept of (0, 5). Since the "or equal to" case is included, the graph of the line is a solid line.

__

You can then locate one of the variables, preferable one with a positive coefficient. (y has a coefficient of +1) Notice its relation to the comparison symbol. Here, we have ( ) +y ≤ ( ). That is, values of <em>y less than</em> {something} will be part of the solution set. This tells you the shading is <em>below the line</em>. (The shading indicates values of x and y that are part of the solution.)

_____

<em>Additional comments</em>

Had the relation been y > {something}, shading would be <em>above the line</em>. You will note that the inequality can also be written ...

  y ≤ x + 5

We can also look at the x-variable to determine where the shading should be. This inequality has the form {something} ≤ x, so x-values <em>greater</em> than those on the boundary line are part of the solution. Since the slope of the line is positive, "right of the line" is the same as "below the line" as far as shading is concerned.

Of course, if the relation had been < instead of ≤, the boundary line would be <em>dashed</em> (not solid) and considered to be <em>not part of the solution</em>.

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Dafna1 [17]

Answer:

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Step-by-step explanation:

Simplify the following:

c (4 b^3 + 3 a) + b (2 c b^2 - 6 a c)

Hint: | Factor common terms out of 2 c b^2 - 6 a c.

Factor 2 c out of 2 c b^2 - 6 a c:

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Hint: | Pull a common factor out of c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a).

Factor c out of c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a), resulting in c ((4 b^3 + 3 a) + b×2 (b^2 - 3 a)):

c (4 b^3 + 3 a + 2 b (b^2 - 3 a))

Hint: | Distribute 2 b over b^2 - 3 a.

2 b (b^2 - 3 a) = 2 b^3 - 6 a b:

c (4 b^3 + 3 a + 2 b^3 - 6 a b)

Hint: | Group like terms in 4 b^3 + 3 a - 6 a b + 2 b^3.

Grouping like terms, 4 b^3 + 3 a - 6 a b + 2 b^3 = (4 b^3 + 2 b^3) - 6 a b + 3 a:

c (4 b^3 + 2 b^3) - 6 a b + 3 a

Hint: | Add like terms in 4 b^3 + 2 b^3.

4 b^3 + 2 b^3 = 6 b^3:

c (6 b^3 - 6 a b + 3 a)

Hint: | Factor out the greatest common divisor of the coefficients of 6 b^3 - 6 a b + 3 a.

Factor 3 out of 6 b^3 - 6 a b + 3 a:

Answer: c×3 (2 b^3 - 2 a b + a)

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<h3>What is experimental design?</h3>
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Hence, amongst all the given options, The Option A best explains the dual experiments: "In the experimental group, a chosen variable is altered in a known way. In the control group, that chosen variable is not altered so a comparison can be made."

To learn more about experimental design, refer to the link:brainly.com/question/17274244

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