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r-ruslan [8.4K]
3 years ago
11

Question 1 (1 point)

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

c=d*π

Step-by-step explanation:

d=diameter=4

π=22÷7

c=22÷7*4

c=88÷7

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Simplify this algebraic expression completely 10y-3(y+5)
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Answer:

7y - 15

Step-by-step explanation:

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A single die is rolled twice. find the probability of rolling an odd number the first time and a number greater than 3 the secon
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Please help<br><br> In which table does y vary directly with x?
grigory [225]

Answer:

Table D

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

<u><em>Verify each case</em></u>

<em>Table A</em>

For x=1, y=3

Find the value of k

k=y/x -----> k=3/1=3

For x=2, y=9

Find the value of k

k=y/x -----> k=9/2=4.5

the values of k are different

therefore

The table A not represent a direct variation

<em>Table B</em>

For x=1, y=-5

Find the value of k

k=y/x -----> k=-5/1=-5

For x=2, y=5

Find the value of k

k=y/x -----> k=5/2=2.5

the values of k are different

therefore

The table B not represent a direct variation

<em>Table C</em>

For x=1, y=-18

Find the value of k

k=y/x -----> k=-18/1=-18

For x=2, y=-9

Find the value of k

k=y/x -----> k=-9/2=-4.5

the values of k are different

therefore

The table A not represent a direct variation

<em>Table D</em>

For x=1, y=4

Find the value of k

k=y/x -----> k=4/1=4

For x=2, y=8

Find the value of k

k=y/x -----> k=8/2=4

For x=3, y=12

Find the value of k

k=y/x -----> k=12/3=4

All the values of k are equal

therefore

The table D represent a direct variation or proportional relationship

The linear equation is y=4x

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You draw two marbles without replacement from a bag containing 2 green marbles and 3 black marbles. What are the possible outcom
Step2247 [10]
2 greens
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Hope this helps ;p have a nice day!

~pam
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