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frutty [35]
3 years ago
10

Plz help 8th grade Math

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

C

Step-by-step explanation:

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Expand & simplify 4(t+2)+6(t-4)
kondaur [170]

Answer:

10t - 16

Step-by-step explanation:

4(t + 2)+ 6(t - 4)

4t + 8 + 6t -24

10t - 16

8 0
3 years ago
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What is the coefficient in the expression 10x + 8 I need help
koban [17]

Answer:

10

Step-by-step explanation:

A coefficient is a multiplicative factor. Whatever is in front of the variable is a coefficient

5 0
3 years ago
A bag contains 4 red and 6 green gumballs. if you select 5 of them without looking, how many ways can you get exactly 3 red or e
marusya05 [52]
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,

4C3 = 4!/3!(4 - 3)! = 4 ways

If you want to get 2 green out of the total 6, then that would be 6C2. That means,

6C2 = 6!/2!(6-2)! = 15 ways

Therefore, there are a total of 4+15 = <em>19 ways</em>.
8 0
3 years ago
a cube is dilated by a scale factor of 3/4 to create a new cube. what is the surface area of the new cube.
jeka57 [31]

Answer:

9/16

Step-by-step explanation:

i took the test ;)

7 0
3 years ago
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Please try your best and show your work and I will give brainliest!
dimulka [17.4K]

Answer:

Part A: impossible

Part B: Either equal or blue

Part C: 9 green and 2 blue were added

Step-by-step explanation:

Part A:

The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.

Part B:

I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.

Part C:

The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.

I hope this helps and please mark me as brainliest!

5 0
2 years ago
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