Complete Question
In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?
Answer:
The probability is 
Yes the result is reasonably close
Step-by-step explanation:
From the question we are told that
The number of of green peas is 
The number of yellow peas is 
The sample size is 
The probability of getting an offspring pea that is green is mathematically represented as



Comparing
to
we see that the result is reasonably close
Answer:
Step-by-step explanation:
6x+9=63
6x=63-9
6x=54
x=54/6
x=9
I encourage you to figure out the justification yourself.
The outlier would be shown as a dot so the answer is B. 45
The interquartile range is 28 - 18 = 10
A simple rule is that points more than 1.5xIRQ above or below the medians is an outlier and is shown as a point.
28 + 1.5x10 = 43. 45 is above this value.
Answer:
17.9
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
(25-16) / h = h / 16
9/h = h/16
=144 ( 9 x 16)
h₂ = 144
h= square root 144
h= 12